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Integrate the rational functions.
Now,
Now, let x2 = t
2xdx = dt
Thus, …(1)
Let
1 = A(t + 3) + B(t + 1)……………….(2)
Substituting t = -3 and -1 in (2), we get
A = and B =
[Hint: multiply numerator and denominator by xn-1 and put xn=t]
[Hint: Put ex = t]