Find the area of the region in the first quadrant enclosed by x-axis, line and the circle x2 + y2 = 4.
The equations are and the circle
From the figure we can see that the x-axis is the area OAB and it si shown by shaded region.
Now, the point of intersection of the line and the circle in the first quadrant is .
Area OAB = Area ΔOCA + Area ACB
Area of ΔOCA =
Area of ABC =
Therefore, required area is = .