Find the area bounded by the curve x2 = 4y and the line x = 4y – 2.
It is given that the area of the region bounded by the parabola x2 = 4y and x = 4y - 2.
Let A and B be the points of intersection of the line and parabola.
Coordinates of point A are
Coordinates of point B are (2, 1).
Now, draw AL and BM perpendicular to x axis.
We can see that
Area OBAO = Area OBCO + Area OAC) …(1)
Now, Area OBCA = Area OMBC – Area of OMBO
Area OACO = Area OLAC – Area of OLAO
Therefore, the required area is