Find the area of the circle 4x2 + 4y2 = 9 which is interior to the parabola x2 = 4y.
It is given that of circle, 4x2 + 4y2 = 9 and parabola x2 = 4y.
On solving the above two equations, we get the point of intersection
We can see that the required area is symmetrical about y axis.
Thus, Area OBCDO = 2 × Area OBCO
Let us draw BM perpendicular to OA.
⇒ The coordinates of M are (, 0).
Then, Area OBCO = Area OMBCO – Area OMCO
Therefore, the required area OBCDO is