Find the area bounded by curves (x – 1)2 + y2 = 1 and x2 + y2 = 1.
It is given that area of circle, (x – 1)2 + y2 = 1 and x2 + y2 = 1.
On solving the above two equations, we get the point of intersection
We can see that the required area is symmetrical about x axis.
Thus, Area OBCAO = 2 × Area OCAO
Let us draw AM perpendicular to OC.
⇒ The coordinates of M are (, 0).
Then, Area OCAO = Area OMAO + Area MCAM
Therefore, the required area OBCAO