It is given that area of circle, (x – 1)² + y² = 1 and x² + y² = 1.

On solving the above two equations, we get the point of intersection

We can see that the required area is symmetrical about x axis.

Thus, Area OBCAO = 2 × Area OCAO

Let us draw AM perpendicular to OC.

⇒ The coordinates of M are (, 0).

Then, Area OCAO = Area OMAO + Area MCAM

Therefore, the required area OBCAO