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Find the area of the region bounded by the curves y = x2 + 2, y = x, x = 0 and x = 3.
It is given that equation of curve are y = x2 + 2, y = x, x = 0 and x = 3. The required area is shown by shaded region.
= [9 + 6] -
= 15 –
Find the area of the circle 4x2 + 4y2 = 9 which is interior to the parabola x2 = 4y.
Find the area bounded by curves (x – 1)2 + y2 = 1 and x2 + y2 = 1.
Using integration find the area of region bounded by the triangle whose vertices are (– 1, 0), (1, 3) and (3, 2).
Using integration find the area of the triangular region whose sides have the equations y = 2x + 1, y = 3x + 1 and x = 4.
Smaller area enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is
Area lying between the curves y2 = 4x and y = 2x is