Find points on the x – axis, each of which is at a distance of 10 units from the point A(11, – 8).

Let the point be X(x,0)


XA = 10


By distance formula, as shown below:



XA = √{(11 – x)2 + (– 8 – 0)2}


10 = √{(11 – x)2 + (– 8)2}


10 = √{121 + x2 – 22x + 64}


10 = √{185 + x2 – 22x}


Squaring both sides we get


100 = (185 + x2 – 22x)


85 + x2 – 22x = 0


x2 – 22x + 85 = 0


(x – 5)(x – 17)


× = 5 or × = 17


The points are (5, 0) and (17, 0)


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