If the coordinates of points A and B are (– 2, – 2) and (2, – 4) respectively, find the coordinates of the point P such that AP = 3/7 AB, where P lies on the line segment AB.

Let the point P(x,y) divides AB


Then


X = (m1x2 + m2x1)/ m1 + m2


= (3 × 2) + 4x (– 2))/ 3 + 4


= (6 – 8)/7


= – 2/7


Y = (m1y2 + m2y1)/ m1 + m2


= (3 × (– 4) + 4 × (– 2))/ 7


= (– 12 – 8)/ 7


= – 20 / 7



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