If the coordinates of points A and B are (– 2, – 2) and (2, – 4) respectively, find the coordinates of the point P such that AP = 3/7 AB, where P lies on the line segment AB.
Let the point P(x,y) divides AB
Then
X = (m1x2 + m2x1)/ m1 + m2
= (3 × 2) + 4x (– 2))/ 3 + 4
= (6 – 8)/7
= – 2/7
Y = (m1y2 + m2y1)/ m1 + m2
= (3 × (– 4) + 4 × (– 2))/ 7
= (– 12 – 8)/ 7
= – 20 / 7