Points P, Q and R in that order are dividing a line segment joining A(1, 6) and B(5, – 2) in four equal parts. Find the coordinates of P, Q and R.
P divides the segment AB in ratio 1:3
Q divides the segment AB in ratio 2:2
R divides the segment AB in ratio 3:1
For coordinates of P
X = (m1x2 + m2x1)/ m1 + m2
= (1 × 5 + 3 × 1)/1 + 3
= (5 + 3) /4
= 8/4 = 2
Y = (m1y2 + m2y1)/ m1 + m2
= (1× (– 2) + 3 × 6)/4
= (– 2 + 18)/5
= 16 / 4 = 4
= (2, 4)
For coordinates of Q
X = (m1x2 + m2x1)/ m1 + m2
= (2x 5 + 2x 1)/4
= (10 + 2) /4
= 12/4 = 3
Y = (m1y2 + m2y1)/ m1 + m2
= (2 × (– 2) + 2 × 6)/ 4
= (– 4 + 12)/4
= 8 / 4 = 2
= (3,2)
For coordinates of R
X = (m1x2 + m2x1)/ m1 + m2
= (3x 5 + 1x 1)/4
= (15 + 1) /4
= 16/4 = 4
Y = (m1y2 + m2y1)/ m1 + m2
= (3 × (– 2) + 1 × 6)/ 4
= (– 6 + 6)/4
= 0/ 4 = 0
= (4,0)
∴ the coordinates are P(2, 4), Q(3, 2), R (4, 0)