Find the coordinates of a point A, where AB is a diameter of a circle with centre C(2, – 3) and the other end of the diameter is B(1, 4).

Let the coordinates of A be × & y. So A(X,Y) and B(1,4)


2 = (m1x2 + m2x1)/ m1 + m2


2 = (1 × 1 + 1 × X)/1 + 1


2 = (1 + X) /2


1 + X = 4


× = 3


– 3 = (m1y2 + m2y1)/ m1 + m2


– 3 = (1× 4 + 1 × Y)/2


– 3 = (4 + Y)/2


(4 + Y) = – 6


Y = – 10


A(3, – 10)


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