Find the coordinates of a point A, where AB is a diameter of a circle with centre C(2, – 3) and the other end of the diameter is B(1, 4).
Let the coordinates of A be × & y. So A(X,Y) and B(1,4)
2 = (m1x2 + m2x1)/ m1 + m2
2 = (1 × 1 + 1 × X)/1 + 1
2 = (1 + X) /2
1 + X = 4
× = 3
– 3 = (m1y2 + m2y1)/ m1 + m2
– 3 = (1× 4 + 1 × Y)/2
– 3 = (4 + Y)/2
(4 + Y) = – 6
Y = – 10
A(3, – 10)