Find the ratio in which the point (– 3, k) divides the join of A(– 5, – 4) and B(– 2, 3). Also, find the value of k. [CBSE 2007]
– 3 = (m1x2 + m2x1)/ m1 + m2
– 3 = (m1 × (– 2) + m2 (– 5))/ m1 + m2
– 3 = (– 2m1 – 5m2 ) / m1 + m2
– 2m1 – 5m2 = – 3(m1 + m2 )
2m1 + 5m2 = 3(m1 + m2 )
m1 – 2m2 = 0
m1:m2 = 1:2
Now,
K = (m1y2 + m2y1)/ m1 + m2
K = (m1 × 3 + m2(– 4))/ m1 + m2
K = (3m1 – 4m2 ) / m1 + m2
3m1 – 4m2 = k(m1 + m2)
Putting the values of m1 & m2
k = 2/3
Hence,2:1, k = 2/3