If three consecutive vertices of a parallelogram ABCD are A(1, – 2), B(3, 6) and C(5, 10), find its fourth vertex D.
Coordinate of mid – point of AC = {(1 + 5)/2,(– 2 + 10)/2}
implies (3,4)
This is equal to the coordinates of mid – point of BD
3 = (3 + x)/2
6 = 3 + x
x = 3
4 = (6 + y)/2
8 = (6 + y)
y = 2
Hence, D(3, 2)