Find the area of ΔABC whose vertices are:

A(1, 2), B(–2, 3) and C(–3, –4)


Area of triangle


= 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


= 1/2(1(–2 + 3)–2(–4–2)–3(2–3))


= 1/2(1 + 12 + 3)


= 8 sq units


1