Find the area of ΔABC whose vertices are:

A(–5, 7), B(–4, –5) and C(4, 5)


Area of triangle


= 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


= 1/2(–5(–5–5)–4(5–7) + 4(7 + 5))


= 1/2(–50 + 8 + 48)


= 5 sq units


1