If the vertices of LABC be A(1, –3), B(4, p) and C(–9, 7) and its area is 15 square units, find the values of p.
Area = 15
⇒ Δ = 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))
15 = 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))
15 = 1/2(1(p–7) + 4(7 + 3)–9(–3–p))
15 = 1/2(10p + 16)
|10p + 16| = 30
10p + 16 = 30 or –30
Hence, p = −9 or p = −3.