If the vertices of LABC be A(1, –3), B(4, p) and C(–9, 7) and its area is 15 square units, find the values of p.


Area = 15


Δ = 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


15 = 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


15 = 1/2(1(p–7) + 4(7 + 3)–9(–3–p))


15 = 1/2(10p + 16)


|10p + 16| = 30


10p + 16 = 30 or –30


Hence, p = 9 or p = 3.


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