Prove that the points A(a, 0), B(0, b) and C(1, 1) are collinear, if

To show that the points are collinear, we show that the area of triangle is equilateral = 0


Δ = 0


Δ = 1/2{x1(y2−y3) + x2(y3−y1) + x3(y1−y2)} = 0


Δ = 1/2{a(b– 1) + 0 (1– 0) + 1 (0– b)} = 0


(ab–a–b) = 0


Dividing the equation by ab.


1–1/b–1/a


1–(1/a + 1/b)


1–1 = 0


Hence collinear.


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