Points A(-1, y) and B(5, 7) lie on a circle with centre O(2, - 3y). Find the values of y.
The distance of any point which lies on the circumference of the circle from the centre of the circle is called radius.
∴ OA = OB = Radius of given Circle
taking square on both sides, we get-
OA2 = OB2
⇒ (-1-2)2 + [y-(-3y)]2 = (5-2)2 + [7-(-3y)]2
[using distance formula, the distance between points (x1,y1) and (x2,y2) is equal to units.]
⇒ 9 + 16y2 = 9 + (7 + 3y)2
⇒ 16y2 = 49 + 42y + 9y2
⇒ 7y2 - 42y - 49 = 0
⇒ 7(y2-6y-7) = 0
⇒ y2-7y + y-7 = 0
⇒ y(y-7) + 1(y-7) = 0
⇒ (y + 1)(y-7) = 0
∴ y = 7 or y = -1
Thus, possible values of y are 7 or -1.