If the centroid of ΔABC having vertices A(a, b), B(b, c) and C(c, a) is the origin, then find the value of (a + b + c).

Every triangle has exactly three medians, one from each vertex, and they all intersect each other at a common point which is called centroid.


fjccnmmc.png


fig.5


In the fig.5, Let AD, BE and CF be the medians of ΔABC and point G be the centroid.


We know that-


Centroid of a Δ divides the medians of the Δ in the ratio 2:1.


Mid-point of side BC i.e. coordinates of point D is given by



Let the coordinates of the centroid G be (x,y).


Since centroid G divides the median AD in the ratio 2:1 i.e.


AG:GD = 2:1


using section-formula, the coordinates of centroid is given by-




Now, according to question-


Centroid of ΔABC having vertices A(a, b), B(b, c) and C(c, a) is the origin.



Thus, the value of a + b + c is 0.


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