If the centroid of ΔABC having vertices A(a, b), B(b, c) and C(c, a) is the origin, then find the value of (a + b + c).
Every triangle has exactly three medians, one from each vertex, and they all intersect each other at a common point which is called centroid.
fig.5
In the fig.5, Let AD, BE and CF be the medians of ΔABC and point G be the centroid.
We know that-
Centroid of a Δ divides the medians of the Δ in the ratio 2:1.
Mid-point of side BC i.e. coordinates of point D is given by
Let the coordinates of the centroid G be (x,y).
Since centroid G divides the median AD in the ratio 2:1 i.e.
AG:GD = 2:1
∴ using section-formula, the coordinates of centroid is given by-
Now, according to question-
Centroid of ΔABC having vertices A(a, b), B(b, c) and C(c, a) is the origin.
Thus, the value of a + b + c is 0.