The point on x-axis which is equidistant from points A(-1, 0) and B(5, 0) is

For the point to be equidistant, the point has to be the midpoint of the line joining the points A and B.


If P(x, y) is the midpoint of the line joining AB then By Midpoint Formula we have,


and y


Finding x co-ordinate of midpoint:




x = 2


Finding y- co-ordinate of midpoint:



y = 0


Therefore the point which is equidistant from A and B is P(2,0).

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