The point on x-axis which is equidistant from points A(-1, 0) and B(5, 0) is
⇒ For the point to be equidistant, the point has to be the midpoint of the line joining the points A and B.
⇒ If P(x, y) is the midpoint of the line joining AB then By Midpoint Formula we have,
⇒ and y
Finding x co-ordinate of midpoint:
⇒
⇒
⇒ x = 2
Finding y- co-ordinate of midpoint:
⇒
⇒ y = 0
Therefore the point which is equidistant from A and B is P(2,0).