The perimeter of the triangle with vertices (0, 4), (0, 0) and (3, 0) is

The perimeter is the addition of lengths of all sides.


Let the points be A = (0, 4), B = (0, 0) and C = (3, 0).


The distance between any two points P1(x1, y1) and P2(x2, y2) is given by the following formula:



Distance AB =


=


= 4


Distance BC =


=


= 3


Distance AC =


= √(9 + 16)


= √25


= 5


Perimeter = 3 + 4 + 5


= 12


Therefore the perimeter of triangle is 12.

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