The perimeter of the triangle with vertices (0, 4), (0, 0) and (3, 0) is
The perimeter is the addition of lengths of all sides.
Let the points be A = (0, 4), B = (0, 0) and C = (3, 0).
The distance between any two points P1(x1, y1) and P2(x2, y2) is given by the following formula:
⇒
⇒ Distance AB =
=
= 4
⇒ Distance BC =
=
= 3
⇒ Distance AC =
= √(9 + 16)
= √25
= 5
∴ Perimeter = 3 + 4 + 5
= 12
Therefore the perimeter of triangle is 12.