Which point on the x-axis is equidistant from the points A(7, 6) and B(-3, 4)?
⇒ Point on x-axis means its y-coordinate is zero.
⇒ Let the point be P(x, 0)
Using the distance formula,
⇒
⇒ Distance AP = Distance BP
⇒ (x-7)2 + (0-6)2 = (x + 3)2 + (0-4)2
⇒ x2 + 49-14x + 36 = x2 + 9 + 6x + 16
⇒ 49-9 + 36-16 = 6x + 14x
⇒ 40 + 20 = 20x
⇒ x = 60/20
x = 3
Therefore the coordinate of P is (3,0).