Which point on the x-axis is equidistant from the points A(7, 6) and B(-3, 4)?

Point on x-axis means its y-coordinate is zero.


Let the point be P(x, 0)


Using the distance formula,



Distance AP = Distance BP


(x-7)2 + (0-6)2 = (x + 3)2 + (0-4)2
x2 + 49-14x + 36 = x2 + 9 + 6x + 16


49-9 + 36-16 = 6x + 14x


40 + 20 = 20x


x = 60/20


x = 3


Therefore the coordinate of P is (3,0).

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