If A(4, 2), B(6, 5) and C(1, 4) be the vertices of ABC and AD is a median, then the coordinates of D are

Since the AD is median, it divides the line BC into two equal halves. So D acts as the midpoint of line BC.


If D(x, y) is the midpoint of the line joining BC then By Midpoint Formula we have,


and y


Finding x co-ordinate of midpoint:




x = 7/2


Finding y- co-ordinate of midpoint:



y = 9/2


Therefore the point which is equidistant from A and B is P(7/2,9/2).

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