If A(4, 2), B(6, 5) and C(1, 4) be the vertices of ∆ABC and AD is a median, then the coordinates of D are
Since the AD is median, it divides the line BC into two equal halves. So D acts as the midpoint of line BC.
If D(x, y) is the midpoint of the line joining BC then By Midpoint Formula we have,
⇒ and y
Finding x co-ordinate of midpoint:
⇒
⇒
⇒ x = 7/2
Finding y- co-ordinate of midpoint:
⇒
⇒ y = 9/2
Therefore the point which is equidistant from A and B is P(7/2,9/2).