In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

2x + 3y – z = 5

The eq. of the plane

2x + 3y-z = 5

Direction ratio of the normal (2, 3, -1)

This is the form of

lx + my + nz = d (∴ d = Distance of the normal from the origin.)

1