In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
2x + 3y – z = 5
The eq. of the plane
2x + 3y-z = 5
Direction ratio of the normal (2, 3, -1)
This is the form of
lx + my + nz = d (∴ d = Distance of the normal from the origin.)
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