In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
5y + 8 = 0
The eq. of the plane
0x-5y + 0z = 8
Direction ratio of the normal (0, -5, 0)
= 5
This is the form of
lx + my + nz = d (∴ d = Distance of the normal from the origin.)
Direction cosine = 0, -1, 0
1