Find the equations of the planes that passes through three points.
(1, 1, –1), (6, 4, –5), (–4, –2, 3)
The given points are (1, 1, -1), (6, 4, -5), (-4, -2, 3).
Let,
= 1(12 - 10) – 1(18 - 20) -1 (-12 + 16)
= 2 + 2 – 4
= 0
Since, the value of determinant is 0.
Therefore, these points are collinear as there will be infinite planes passing through the given 3 points.
6