In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.
2x – 2y + 4z + 5 = 0 and 3x – 3y + 6z – 1 = 0
The eq. of the given planes are
2x – 2y + 4z + 5 =0 and x – 2y + 5 = 0
Two planes are ⊥ if the direction ratio of the normal to the plane is
a1a2 + b1b2 + c1c2 = 0
6 + 6 + 24
36 ≠ 0
∴ Both the planes are not ⊥ to each other.
Two planes are || to each other if the direction ratio of the normal to the plane is
Thus, the given planes are || to each other.
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