In each of the question verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:
x + y = tan–1y : y2y′ + y2 + 1 = 0
It is given that x + y = tan-1y
Now, differentiating both sides w.r.t. x, we get,
Now, Substituting the values of y’ in the given differential equations, we get,
LHS = y2y’ + y2 + 1 =
= -1 – y2 + y2 + 1
= 0 = RHS
Therefore, the given function is the solution of the corresponding differential equation.