In each of the question, form a differential equation representing the given family of curves by eliminating arbitrary constants a and b.

y = e^{x} (a cos x + b sin x)

It is given that y = e^{x}(acosx + bsinx) ------(1)

Now, differentiating both w.r.t. x, we get,

y’ = e^{x}(acosx + bsinx) + e^{x}(-asinx + bcosx)

⇒ y’ = e^{x}[(a + b)cosx – (a – b)sinx)] ------(2)

Again, differentiating both sides w.r.t. x, we get,

y” = e^{x}[(a + b)cosx – (a – b)sinx)] + e^{x}[-(a + b)sinx – (a – b)cosx)]

⇒ y” = e^{x}[2bcosx – 2asinx]

⇒ y” = 2e^{x}(bcosx – asinx) ----(3)

Adding equation (1) and (3), we get,

⇒ 2y + y” = 2y’

Therefore, the required differential equation is 2y + y” = 2y’= 0.

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