Here, putting x = kx and y = ky

= k⁰.f(x,y)

Therefore, the given differential equation is homogeneous.

To solve it we make the substitution.

y = vx

Differentiating eq. with respect to x, we get

Integrating both sides, we get

Put, logv – 1 = t

logt

log(logv - 1)

∴ log(logv - 1) – log(v) = log(x) + log(c) (From (i) eq.)

The required solution of the differential equation.