For each of the differential equations in question, find the particular solution satisfying the given condition:
x2dy + (xy + y2)dx = 0; y = 1 when x = 1
x2dy + (xy + y2)dx = 0
Here, putting x = kx and y = ky
= k0.f(x,y)
Therefore, the given differential equation is homogeneous.
x2dy + (xy + y2)dx = 0
To solve it we make the substitution.
y = vx
Differentiating eq. with respect to x, we get
Integrating both sides, we get
y = 1 when x = 1
3x2y = y + 2x
y + 2x = 3x2y
The required solution of the differential equation.