(A) (4x + 6y + 5)dy – (3y + 2x + 4)dx = 0

It cannot be homogeneous as we can see that (4x + 6y + 5) is not homogeneous.

(B) (xy)dx – (x³ + y³)dy = 0

It cannot be homogeneous as the xy which multiplies with dx and x³ + y³ which multiplies with dy are not of same degree.

(C) (x³ + 2y²)dx + 2xy dy = 0

Similarly, it cannot be homogeneous as the x³ + 2y² which multiplies with dx and 2xy which multiplies with dy are not of same degree.

(D) y²dx + (x² – xy – y²)dy = 0

Here, putting x = kx and y = ky

= k⁰.f(x,y)

Therefore, the given differential equations is homogeneous.