For each of the differential equations given in question, find the general solution:
(1 + x2)dy + 2xy dx = cot x dx (x ≠ 0)
It is given that ![]()
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This is equation in the form of
(where, p =
and Q =
)
Now, I.F. = ![]()
Thus, the solution of the given differential equation is given by the relation:
y(I.F.) = ![]()
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Therefore, the required general solution of the given differential equation is
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