It is given that

This is equation in the form of (where, p = 2tanx and Q =sinx )

Now, I.F. =

Thus, the solution of the given differential equation is given by the relation:

y(I.F.) =

----------------(1)

Now, it is given that y = 0 at x =

⇒ 0 = 2 + C

⇒ C = -2

Now, Substituting the value of C = -2 in (1), we get,

⇒ y = cosx – 2cos²x

Therefore, the required general solution of the given differential equation is

y = cosx – 2cos²x.