Mathematics Part-II

Book: Mathematics Part-II

Chapter: 9. Differential Equations

Subject: Maths - Class 12th

Q. No. 15 of Exercise 9.6

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15

For each of the differential equations given in question, find a particular solution satisfying the given condition:

It is given that

This is equation in the form of (where, p = -3cotx and Q = sin2x)


Now, I.F. =


Thus, the solution of the given differential equation is given by the relation:


y(I.F.) =




⇒ y cosec3x = 2cosecx + C


⇒ y =


⇒ y = -2sin2x + Csin3x--------------(1)


Now, it is given that y = 2 when x =


Thus, we get,


2 = -2 + C


⇒ C = 4


Now, Substituting the value of C = 4 in (1), we get,


y = -2sin2x + 4sin3x


⇒ y = 4sin3x - 2sin2x


Therefore, the required general solution of the given differential equation is


y = 4sin3x - 2sin2x.


15

Chapter Exercises

Exercise 9.1
Exercise 9.2
Exercise 9.3
Exercise 9.4
Exercise 9.5
Exercise 9.6
Miscellaneous Exercise

More Exercise Questions

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