Prove that x2 – y2 = c (x2 + y2)2 is the general solution of differential equation (x3–3xy2) dx = (y3–3x2y)dy, where c is a parameter.
It is given that (x3–3xy2) dx = (y3–3x2y)dy
- --------(1)
Now, let us take y = vx
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Now, substituting the values of y and
in equation (1), we get,
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On integrating both sides we get,
--------(2)
Now, ![]()
---------(3)
Let ![]()
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Now, ![]()
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Let v2 = p
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Now, substituting the values of I1 and I2 in equation (3), we get,

Thus, equation (2), becomes,


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⇒ (x2 – y2)2 = C’4(x2 + y2 )4
⇒ (x2 – y2) = C’2(x2 + y2 )
⇒ (x2 – y2) = C(x2 + y2 ), where C = C’2
Therefore, the result is proved.