Show that the general solution of the differential equation 
is given by (x + y + 1) = A (1 – x – y – 2xy), where A is parameter.
It is given that 
On integrating both sides, we get,
Let 
Then,
Now, let A = 
, then, we have,
8
Show that the general solution of the differential equation is given by (x + y + 1) = A (1 – x – y – 2xy), where A is parameter.
It is given that
On integrating both sides, we get,
Let
Then,
Now, let A = , then, we have,