The general solution of the differential equation ex dy + (y ex + 2x) dx = 0 is
It is given that exdy + (yex + 2x) dx = 0
This is equation in the form of 
(where, p = 1 and Q = -2xe-x)
Now, I.F. = 
Thus, the solution of the given differential equation is given by the relation:
y(I.F.) = 
⇒ yex = -x2 + C
⇒ yex + x2 = C
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