If A and B are two events such that P (A) = 1/4 , P (B) = 1/2 and P (A ∩ B) = 1/8, find P (not A and not B).
Given: P (A) =, P (B) = and P (A ∩ B) =
P(not A and not B) = P(A’ ∩ B’)
As, { A’ ∩ B’ =(A ∪ B)’}
⇒ P(not A and not B) = P ((A ∪ B)’)
= 1 - P (A ∪ B)
= 1- [P(A) + P(B) - P (A ∩ B)]