The mean of the numbers obtained on throwing a die having written 1 on three faces, 2 on two faces and 5 on one face is
Given: A die having written 1 on three faces, 2 on two faces and 5 on one face.
Let X be the random variable representing a number on given die.
Then X can take any value of 1, 2 or 5.
The total numbers is six.
Now
P(X = 1) ![]()
P(X = 2) ![]()
P(X = 5) ![]()
Hence, the required probability distribution is,
X | 1 | 2 | 5 |
P(X) |
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|
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Therefore Expectation of X E(X):

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⇒ E(X) = 2
Hence, the correct answer is (B).