In a box containing 100 bulbs, 10 are defective. The probability that out of a sample of 5 bulbs, none is defective is
In this question, let us assume X represent the number of times selecting defected bulbs in a random sample of given 5 bulbs
Also, the repeated selection of defective bulbs from a box are the Bernoulli trials
Clearly, we have X has the binomial distribution where n = 5 and ![]()
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∴ ![]()
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Hence, probability that none bulb is defective = P (X = 0)
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∴ option C is correct