Suppose that 90% of people are right-handed. What is the probability that at most 6 of a random sample of 10 people are right-handed?
It is given in the question that,
90% of the people are right handed
Let p denotes the probability of people that are right handed and q denotes the probability of people that are left handed
∴
And,
Now, by using the binomial distribution probability of having more than 6 right handed people can be given as:
Hence, the probability of having more than 6 right handed people:
= 1 – P (More than 6 people are right handed)
=