In a hurdle race, a player has to cross 10 hurdles. The probability that he will clear each hurdle is 5/6. What is the probability that he will knock down fewer than 2 hurdles?

In this question,

Let us assume p be the probability of player that will clear the hurdle while q be the probability of player that will knock down the hurdle



And,



Let us also assume X be the random variable that represents the number of times the player will knock down the hurdle


By binomial distribution,


Hence, probability (players knocking down less than 2 hurdles) = P (X < 2)


= P (X = 0) + P (X = 1)



=


=


=


6