In a hurdle race, a player has to cross 10 hurdles. The probability that he will clear each hurdle is 5/6. What is the probability that he will knock down fewer than 2 hurdles?
In this question,
Let us assume p be the probability of player that will clear the hurdle while q be the probability of player that will knock down the hurdle
∴
And,
Let us also assume X be the random variable that represents the number of times the player will knock down the hurdle
∴ By binomial distribution,
Hence, probability (players knocking down less than 2 hurdles) = P (X < 2)
= P (X = 0) + P (X = 1)
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