If a leap year is selected at random, what is the chance that it will contain 53 Tuesdays?
We know that, in a leap year there are total 366 days, 52 weeks and 2 days
Now, in 52 weeks there are total 52 Tuesdays
∴ Probability that the leap year will contain 53 Tuesdays is equal to the probability of remaining 2 days will be Tuesdays
Thus, the remaining two days can be:
(Monday and Tuesday), (Tuesday and Wednesday), (Wednesday and Thursday), (Thursday and Friday), (Friday and Saturday), (Saturday and Sunday) and (Sunday and Monday)
∴ Total Number of cases = 7
Cases in which Tuesday can come = 2
Hence, probability (leap year having 53 Tuesdays)