The half-life of 9038Sr is 28 years. What is the disintegration rate of 15 mg of this isotope?

From the principle of exponential radioactive decay,

we know that


Here, the mass of the isotope is = 15 g


No. of atoms in 15gm of atom is = atoms


And, λ = (0.693/T1/2) where, Half life = 28 × 365 × 86400 = 8.83 × 108 secs


Hence,


The disintegration rate of 15 mg of the isotope will be


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