Evaluate

Let I =

Dividing 5x2 by x2 + 4x + 3 we get 5 as quotient and –(20x + 15) as remainder


So, I =


I = =


I = 5 (2 – 1) -


I = 5 – I1


I1 =


Adding and subtracting 25 in the numerator


I1 =


I1 =


Let x2 + 4x + 3 = t


(2x + 4)dx = dt


I1 =


I1 = 10 log t - []


I1 = 10 log t - []


I1 =


I1 = 10


I1 =


I1 =


I1 =


I1 =


I1 =


I = 5 I1


Substituting I1 in I we get


I = 5 –


= 5 –


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