The radius of a circle is 13 cm and length of one of its chords is 24 cm. Find the distance of the chord from the centre.
Let AB = 24 cm be the chord of the circle with radius AO = 13 cm.
Draw OP ⊥ AB. Join OA according to theorem,
AP=
휤 = 12 cm
In Δ APO, ∠P = 90°
... AO2 = AP2 + OP2
= 122 + OP2
⇒ 132 = 122 + OP2
⇒ OP = 5 cm
Draw OP ⊥ AB. Join OA according to theorem,
AP=
휤 = 12 cmIn Δ APO, ∠P = 90°
... AO2 = AP2 + OP2
= 122 + OP2
⇒ 132 = 122 + OP2
⇒ OP = 5 cm
1