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Find the remainder when
y
3
+ y
2
- 2y + 5
is divided
by
y - 5.
Again, we should evaluate p(5)
Let
p(y) = y
3
+ y
2
- 2y
+ 5
.
.
.
p
(5) = 5
3
+ 5
2
- 2 x 5 + 5
= 125 + 25 - 10 + 5
= 145
Thus, we find that
p
(5) is the remainder when
p(y)
is divided by
y
- 5.
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