If both(x + 1) and (x - 1) are factors of ax3 + x2- 2x + b, find a and b.
Let p(x) = ax3 + x2 - 2x + b Since(x + 1) and (x - 1) are the factors of p(x), ... p(-1) = 0 and p(1) = 0 ... p(- 1) = a(-1)3 + (-1)2- 2(-1) + b = 0 ⇒ - a + 1 + 2 + b = 0 ⇒ a - b = 3 …… (i) Again, p(1) = a(1)3 + (1)2 - 2(1) + b = 0 ⇒ a + 1 - 2 + b = 0 ⇒ a + b = 1 …… (ii) Solving equations (i) and (ii) we get a = 2 and b= -1