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Factorise
(i) 6ab - b
2
+ 12ac - 2bc
(ii) x
2
+ y - xy - x
(iii) x
3
- 2x
2
y + 3xy
2
- 6y
3
(iv) a(a + b - c) – bc
(i) 6ab - b
2
+ 12ac - 2bc
= (6ab - b
2
) + (12ac - 2bc)
= b(6a - b) + 2c(6a - b)
= (6a - b) (b + 2c)
(ii) x
2
+ y - xy - x
= x
2
- xy - x + y
= x(x - y) - (x - y)
= (x - y) (x - 1)
(iii) x
3
- 2x
2
y + 3xy
2
- 6y
3
= (x
3
- 2x
2
y) + (3xy
2
- 6y
3
)
= x
2
(x - 2y) + 3y
2
(x - 2y)
= (x - 2y) (x
2
+ 3y
2
)
(iv) a(a + b - c) - bc
= a
2
+ ab - ac - bc
= a(a + b) - c(a + b)
= (a + b) (a - c)
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