A ladder is placed against a wall such that it just reaches the top of thewall. The foot of the ladder is 1.5 m away from the wall and the ladder isinclined at an angle of 60 owith the ground. Findthe height of the wall.
Given:
Distance of the ladder from the wall, d = BC = 1.5 m
Angle of elevation, θ = 60°
To find: Height of the wall, h:
Solution:
Let AC be the ladder and B be the foot of the wall.
In right angled Δ ABC,
tan [θ] = Opposite / Adjacent
Here θ = 60°
And also the opposite side is AB and the adjacent side is BC
∴ tan 60 o = AB/BC
tan 60 o = AB/BC
AB = BC tan 60 o
We know that BC = 1.5m
= 1.5 × (√ 3)
= 1.5 × 1.732
= 2.598 m
Therefore the height of the wall is 2.598 m.
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